A Poster Can Have A Maximum Perimeter Of 42 Inchem.Org – Fields Of Comedy Crossword Club.Fr

July 8, 2024, 10:58 pm

Next, you subtract 8 from the perimeter which is 26, and the difference is 18. And we can verify that. The area of a square is the side length times itself. Try adding all of these up together. So the perimeter is 78 feet. So this is equal to 36. How would you figure the area of a pentagon?

A Poster Can Have A Maximum Perimeter Of 42 Inches Wide

Still have questions? Let's do 78 minus 21 minus 21. Edit: Ask me if you need help:)(3 votes). Check the full answer on App Gauthmath. Provide step-by-step explanations. And we know how we figure out the perimeter. Unlimited access to all gallery answers. Point your camera at the QR code to download Gauthmath.

A Poster Can Have A Maximum Perimeter Of 42 Inches Max 33

I'm in 4rth grade and I'm trying to figure it out... '(5 votes). And the width would be this length-- or this width, I should say-- this width, which is going to be the same thing as that width right over here. The formula is pi times the radius squared. So it might look something like this. The area of a square is 144 square centimeters.

A Poster Can Have A Maximum Perimeter Of 42 Inches 6 Pockets

Now, they also tell us that the perimeter is 78 feet. So we need to find what positive number times itself would give 144. First, you multiply the width by 2. This is what we needed the two widths to add up to-- plus 42. So one way to back into what the width is is to say, well, look if we sum up all of these lengths, we're going to get 28 feet. And what's that going to be equal to? 'How would you find the perimeter of a circle? A poster can have a maximum perimeter of 42 inches in cm. '

A Poster Can Have A Maximum Perimeter Of 42 Inches In Length

Its length is 21 feet. Grade 11 · 2022-09-17. This means that 9 is the length. Width of printed area = x-3 & length of printed area = y-2: area =. Im bored, school is boring(7 votes). Afterwards, 18/2 = 9. That's the total length-- or I should say the total width-- if we were to take the width down here and add it to the width up here. Let's find: =, for area to be maximum = 0. The area is given in square centimeters, so the side length is in centimeters. A page should have perimeter of 42 inches. The printing area within the page would be determined by - Brainly.com. So let's say that this is the dog pen right over here. We solved the question! Step-by-step explanation: We have, A page should have perimeter of 42 inches. Gauth Tutor Solution. Sal figures out the width of a dog pen.

A Poster Can Have A Maximum Perimeter Of 42 Inches In Cm

Well, we know that 18 plus 18 is equal to 36. And 78 minus 42-- I don't want to make a careless mistake-- 78 minus 42 is going to get me to 36. You add the two widths. Which is, of course, equal to-- 36 plus 42 is equal to 78, which is the perimeter. And let's remind ourselves what 36 feet is. How to calculate depth? You would need a starting place - something like sea level (the surface of the sea), then you would just measure down to the bottom to find depth. So let's draw what it might look like. And if we add them together, we get to 36. Area & perimeter word problem: dog pen (video. Gauthmath helper for Chrome.

A Poster Can Have A Maximum Perimeter Of 42 Inches In Height

This process is called taking the square root. Enjoy live Q&A or pic answer. Mike built a rectangular dog pen that is 21 feet long and has a perimeter of 78 feet. If we added this distance, 21 feet, to this distance, the width, plus 21 feet to the width again, we're going to get to 78 feet.

So we need to figure out the width. If you want to figure out the area, just multiply 4 and 9, and the product is 36 feet squared. 5 inches from each side. I hope this helped a bit!

Check Solution in Our App. And also, which is the fastest and easiest way of doing this?? What is the width of Mike's dog pen? Ask a live tutor for help now. Crop a question and search for answer. And they give us its length. So the side length is 12 centimeters.

For example, what I learned was 78/2 and then take that answer and subtract by the one length that the problem gives you, because the formula that I learned was 2(L+W). And you add the two lengths, plus 21 plus 21. Now, we know something else. So this one down here must be 18. So what are two distances, or what are two numbers that I can add together to get to 36? Want to join the conversation?
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